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Determine the magnitude of the acceleration for the speeding up and slowing down phase.
The magnitude of the acceleration for the speeding up phase is The magnitude of the acceleration for the slowing down phase is Further explanationFrom the v-t graph, we see that:the object at rest at time interval 0 ≤ t < 0.20 and 0.40 ≤ t ≤ 0.60 (in seconds)the object is speeding up and slowing down at interval 0.20 < t 0.40 (in seconds)In physics, acceleration is the rate of change of velocity per unit time.In mathematics, acceleration is the gradient or slope of the line with the vertical axis is velocity (v) and the horizontal axis is time (t).Remember this, The same analogy for the acceleration formula, i.e.The two points that cause the upward-sloping line areWe get the magnitude of the acceleration for the speeding up phase is The two points that cause the downward-sloping line areWe get the magnitude of the acceleration for the speeding up phase is with a negative sign.Note:Positive slope, in other words speeding up, produces a positive sign of acceleration. The acceleration is in a similar direction as the velocity. Example: free-falling object.Negative slope, in other words slowing down, produces a negative sign of acceleration. The acceleration is precisely in the opposite direction as the velocity. Example: the car is slowing or braking.Acceleration is precisely a vector quantity defined as the rate at which an object changes its velocity.Learn moreInterpreting the chart that shows the time, initial velocity, and final velocity tophomeworkanswers.com.com/question/4319751Describing different velocity-time graph lines tophomeworkanswers.com.com/question/11205819Defining the acceleration tophomeworkanswers.com.com/question/6753991Keywords: determine, the magnitude, acceleration, speeding up, slowing down, phase, time interval, at rest, the rate, change, velocity, unit, upward, downward, sloping lines, gradient
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