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Simplify: (sin Θ − cos Θ) − (sin Θ + cos Θ)2
A. (sin θ – cos θ) – (sin θ + cos θ)² = sin θ – cos θ – 1 – sin 2θB. (sin θ – cos θ) – (sin θ + cos θ)² = – 2sin 2θC. (sin θ – cos θ) – (sin θ + cos θ)² = 2Further explanationWe will simplify a form related to trigonometric identity.For more practice and learning, this time we prepare three cases. Most likely one of them is included in the real question being asked.Problem AThe Process:Recall that Recall that Therefore, the result is Problem BThe Process:Let’s expand both squares.Recall that Therefore, the result is Problem CThe Process:Let’s expand both squares.Recall that Therefore, the result is Learn moreWhat is 270° converted to radians tophomeworkanswers.com.com/question/3161884How does the vertical acceleration at point a compare to the vertical acceleration at point c tophomeworkanswers.com.com/question/2746519About vector components tophomeworkanswers.com.com/question/1600633 Keywords: simplify, (sin Θ − cos Θ) − (sin Θ + cos Θ)², (sin Θ − cos Θ)² − (sin Θ + cos Θ)², (sin Θ − cos Θ) + (sin Θ + cos Θ)², trigonometric identity,
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