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The dimensions of a certain ibm machine are 20″ x 17″ x 48″. if the size of the machine is increased proportionately until the sum of its dimensions equals 200″, what will be the increase in the shortest side
The dimensions of the machine are 20,48 and 17. If each dimension is increased by a factor of x;Then new dimensions are20x, 48x and 17xThe sum of the dimensions are ;20x + 48x + 17x = 20085x = 200x = 200/85Therefore each dimension was increased by a factor of x,The new dimension of the shortest side is 17” * 200/85 = 40So the increase in the shortest side ;40-17 = 23”
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