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## Question

The dimensions of a certain ibm machine are 20″ x 17″ x 48″. if the size of the machine is increased proportionately until the sum of its dimensions equals 200″, what will be the increase in the shortest side

## Answer

The dimensions of the machine are 20,48 and 17. If each dimension is increased by a factor of x;Then new dimensions are20x, 48x and 17xThe sum of the dimensions are ;20x + 48x + 17x = 20085x = 200x = 200/85Therefore each dimension was increased by a factor of x,The new dimension of the shortest side is 17” * 200/85 = 40So the increase in the shortest side ;40-17 = 23”

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